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球体３つ描いて　半径１で　同じ直線上に　３色



 I would like to write a Python script in Blender 3.4.1 that imports the math module and　球体３つ描いて　半径１で　同じ直線上に



Sure, I can help you with that! Here's a Python script that imports the math module and creates three spheres with a radius of 1 along the same line:



import bpy
import math

# Create three spheres with a radius of 1 along the same line
for i in range(3):
    x = i * 4  # Set the x-coordinate of the sphere
    y = 0     # Set the y-coordinate of the sphere
    z = 0     # Set the z-coordinate of the sphere

    # Create the sphere
    bpy.ops.mesh.primitive_uv_sphere_add(radius=1, location=(x, y, z))

# Align the spheres along the same line
spheres = bpy.data.objects[-3:]  # Get the three most recently created objects
for i, sphere in enumerate(spheres):
    sphere.location.x = i * 4




This script first imports the Blender Python API module bpy and the standard Python math module.

Then, it creates three spheres with a radius of 1 using a for loop that iterates over the range 0 to 2. Inside the loop, the x, y, and z coordinates of each sphere are set such that the spheres will be spaced 4 units apart along the x-axis.

Finally, the script aligns the spheres along the same line using another for loop that iterates over the three most recently created objects. Inside the loop, the x-coordinate of each sphere is set to its index multiplied by 4, effectively spacing the spheres 4 units apart along the x-axis.

I hope this helps! Let me know if you have any questions.


球体に色を塗って　原点に近い方から　赤　緑　青


Sure, here's an updated version of the script that colors the spheres and arranges them from closest to the origin to farthest, with red, green, and blue:




import bpy
import math

# Create three spheres with a radius of 1 along the same line
spheres = []
for i in range(3):
    x = i * 4  # Set the x-coordinate of the sphere
    y = 0     # Set the y-coordinate of the sphere
    z = 0     # Set the z-coordinate of the sphere

    # Create the sphere and add it to the list of spheres
    bpy.ops.mesh.primitive_uv_sphere_add(radius=1, location=(x, y, z))
    sphere = bpy.context.object
    spheres.append(sphere)

# Create materials for the spheres
red_material = bpy.data.materials.new(name="Red")
red_material.diffuse_color = (1, 0, 0, 1)  # Set the color to red

green_material = bpy.data.materials.new(name="Green")
green_material.diffuse_color = (0, 1, 0, 1)  # Set the color to green

blue_material = bpy.data.materials.new(name="Blue")
blue_material.diffuse_color = (0, 0, 1, 1)  # Set the color to blue

# Color the spheres and arrange them from closest to farthest
spheres.sort(key=lambda sphere: sphere.location.length)  # Sort by distance to the origin
for i, sphere in enumerate(spheres):
    # Assign the material to the sphere
    if i == 0:
        sphere.data.materials.append(red_material)
    elif i == 1:
        sphere.data.materials.append(green_material)
    elif i == 2:
        sphere.data.materials.append(blue_material)

    # Position the sphere along the same line
    sphere.location.x = i * 4

# Set the 3D viewport to show all of the spheres
bpy.ops.view3d.camera_to_view_selected()




This code should create three spheres with a radius of 1 along the same line, create materials for the spheres, color the spheres, and arrange them from closest to farthest from the origin. The code should work correctly now, and all three spheres should be properly colored.





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